A #10*g# mass of carbon dioxide is obtained from the combustion of a #70.2*g# mass of octane. What is the apparent yield?

1 Answer
May 2, 2017

Answer:

We interrogate the stoichiometric combustion equation..............and the yield is under 5%.

Explanation:

#C_8H_18(l) + 25/2O_2(g) rarr 8CO_2(g) + 9H_2O(l)#

#"Moles of octane"=(70.2*g)/(114.23*g*mol^-1)=0.614*mol#

#"Yield of carbon dioxide"=(10.0*gxx100%)/(8xx0.614*molxx44.01*g*mol^-1)=??%#

Are sure you've copied down the appropriate data? The yield seems a little low.