Question #8632c

1 Answer
anor277
May 2, 2017

#"Molarity"=0.10*mol*L^-1#

Explanation:

By definition, #"Molarity"="Moles of solute"/"Volume of solution (L)"#..

And thus, here:

#"Molarity"=((17.1*g)/(342.30*g*mol^-1))/(0.50*L)=0.10*mol*L^-1# with respect to sucrose.

So all I had to do was solve this quotient, and preserve the units of the quotient to give an answer in #mol*L^-1#............i.e. #1/(mol^-1)=1/(1/(mol))=mol# as required...........

Related questions
See all questions in Molarity
Impact of this question
1278 views around the world
You can reuse this answer
Creative Commons License