Question

In a `5*kg` mass of urea, what is the mass of nitrogen?

Answer 1

For a start, urea has a molecular formula of `CH_4N_2O`. I get under `2.5*kg` of nitrogen.

Explanation:

Urea has a formula of `O=C(NH_2)_2`, i.e. each mole of urea supplies two moles of (soluble?) nitrogen.

`"Moles of urea"=(5xx10^3*g)/(60.06*g*mol^-1)=83.25*mol`.

And thus there is a mass of................

`2xx83.25*molxx14.01*g*mol^-1=2333*g`

with respect to nitrogen.