# In a 5*kg mass of urea, what is the mass of nitrogen?

May 4, 2017

For a start, urea has a molecular formula of $C {H}_{4} {N}_{2} O$. I get under $2.5 \cdot k g$ of nitrogen.

#### Explanation:

Urea has a formula of $O = C {\left(N {H}_{2}\right)}_{2}$, i.e. each mole of urea supplies two moles of (soluble?) nitrogen.

$\text{Moles of urea} = \frac{5 \times {10}^{3} \cdot g}{60.06 \cdot g \cdot m o {l}^{-} 1} = 83.25 \cdot m o l$.

And thus there is a mass of................

$2 \times 83.25 \cdot m o l \times 14.01 \cdot g \cdot m o {l}^{-} 1 = 2333 \cdot g$

with respect to nitrogen.