In a #5*kg# mass of urea, what is the mass of nitrogen?

1 Answer
May 4, 2017

Answer:

For a start, urea has a molecular formula of #CH_4N_2O#. I get under #2.5*kg# of nitrogen.

Explanation:

Urea has a formula of #O=C(NH_2)_2#, i.e. each mole of urea supplies two moles of (soluble?) nitrogen.

#"Moles of urea"=(5xx10^3*g)/(60.06*g*mol^-1)=83.25*mol#.

And thus there is a mass of................

#2xx83.25*molxx14.01*g*mol^-1=2333*g#

with respect to nitrogen.