Question #bd6a2

1 Answer
May 4, 2017

Answer:

5.12 M

Explanation:

This is simple plug and chug.

If you know your formula for #"molarity"#,

#color(white)(Aaaaaaaaaa)color(blue)("Molarity" = "moles of solute"/"Liter of solution")#

then you can simply plug where needed to find the molar concentration or molarity

First convert #"mL"->"L"#

#(975cancel"mL")/1 * (1*10^-3" L")/(1 cancel "mL") = 0.975" L"#

#"Molarity" = ("moles of solute")/("Liter of solution")->("5.0 moles of solute")/( 0.975" L of solution")->color(magenta)"5.12 M"#

#"Answer": 5.12" M", "where M is molar"#