Question #88d69

1 Answer
May 8, 2017

Answer:

The sample contains 0.11 mol of #"CO"_2#.

Explanation:

We can use the Ideal Gas Law to solve this problem:.

#color(blue)(bar(ul(|color(white)(a/a)pV = nRTcolor(white)(a/a)|)))" "#

We can rearrange this equation to get

#n = (pV)/(RT)#

STP is defined as 1 bar and 0 °C.

Thus,

#p = "1 bar"#
#V = "2.5 L"#
#R = "0.083 14 bar·L·K"^"-1""mol"^"-1"#
#T = "(0 + 273.15) K" = "273.15 K"#

#n = (1 color(red)(cancel(color(black)("bar"))) × 2.5 color(red)(cancel(color(black)("L"))))/("0.083 14" color(red)(cancel(color(black)("bar·L·K"^"-1")))"mol"^"-1" × 273.15 color(red)(cancel(color(black)("K")))) = "0.11 mol"#