What's #log_5(125)#?

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Answer 1 · 2017-05-08T01:09:23

#x=12#

Let's first see that we can write #log_5(125)# as a number. It might be easier to see it if we use this rule:

#a^b=c <=> log_ac=b#

and so

#5^b=125#

The number it will become is the #b#. It turns out that #5^3=125# and so #b=3# and that is what the log will return:

#log_5(125)=3=x/4#

And now we can solve:

#x=12#