Question #efd49

1 Answer

Answer:

See below

Explanation:

At STP, we know the following:

Temperature = #"273.15 K"# (#0^@ "C")#
Pressure = #1# #"atm"#

Plugging this into the ideal gas law yields:

#PV = nRT#

#=> ("1 atm")V = n("0.0821 L"cdot"atm/mol"cdot"K")("273.15 K")#

#=> V = "22.414 L/mol"*(n)#

Note that all units except #L# will cancel out, due to the dimensions of the #R# value

Therefore, for 1 mol of gas:

#V = "22.414 L"#

There you have it.

Hope that helps :)