# Question 22201

88 g of $\text{CO}$
88 g of $\text{CO}$ contain 88/28.01 × 6.022 × 10^23 = 1.9 × 10^24 atoms of $\text{O}$.
Hence, the mass of $\text{CO}$ that contains 1.9 × 10^24# atoms of $\text{CO}$ is 88 g.