What sort of molecule is #C_17H_31CO_2H#?

1 Answer
May 14, 2017

The formula #C_17H_31CO_2H# has the two degrees of unsaturation, and THUS ONE OLEFINIC bond or cyclic residue........in addition to the carboxyl group.

Explanation:

A saturated carbon molecule with 17 carbons would have 36 hydrogen atoms; we have 32 hydrogens in the formula, and thus there is the one #C=O# bond (of the carboxylate, which of course we knew by the problem's specification), and also an olefinic bond somewhere along the chain OR a ring junction..........