Question #12ed2

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Answer 1 · 2018-01-06T20:46:53

#r=5tanthetasectheta#

We note that:

#x=rcostheta#

#y=rsintheta#

#theta=arctan(y/x)#

Substituting:

#rsintheta=(r^2cos^2theta)/5#

#5rsintheta=r^2cos^2theta#

#1/5r=sintheta/cos^2theta#

#r=5tanthetasectheta#