# Can you represent the reduction of tellurite ion, TeO_3^(2-), to tellurium metal by the oxidation of iodide ion?

May 15, 2017

Iodide anion is oxidized to iodine...........

${I}^{-} \rightarrow \frac{1}{2} {I}_{2} \left(s\right) + {e}^{-}$ $\left(i\right)$

#### Explanation:

${I}^{-} \rightarrow \frac{1}{2} {I}_{2} \left(s\right) + {e}^{-}$ $\left(i\right)$

Tellurite ion is reduced to tellurium metal...........

$T e {O}_{3}^{2 -} + 6 {H}^{+} + 4 {e}^{-} \rightarrow \stackrel{0}{T} e + 3 {H}_{2} O$ $\left(i i\right)$

Mass and charge are balanced in each instance. And so we take $4 \times \left(i\right) + \left(i i\right) :$

$T e {O}_{3}^{2 -} + 4 {I}^{-} + 6 {H}^{+} \rightarrow T e + 2 {I}_{2} + 3 {H}_{2} O$

Which is balanced with respect to mass and charge. Whether it represents an actual chemical reaction, I don't know...........