# Question #27605

May 15, 2017

The question isn't explained properly so I have to assume things

#### Explanation:

Let

• First no. in the consecutive number is $= x$
• Second no. in the consecutive is $= x + 1$
• Third no. in the consecutive is $= x + 2$

Therefore, Sum of three consecutive numbers are

$x + x + 1 + x + 2 = 114$

$3 x + 3 = 114$

$3 x = 114 - 3$

$x = \frac{111}{3}$

$x = 37$

Therefore, you have

• First number $= 37$
• Second number $= 37 + 1 = 38$
• Third number $= 37 + 2 = 39$