# What are the formulae of "stannous bromide" and "stannic bromide"?

For $\text{stannous bromide.............?}$
The material is formed formed from $S {n}^{2 +}$ and $2 \times B {r}^{-}$ ions.......... And hence the formula is $S n B {r}_{2}$.
On the other hand, the formula for $\text{stannic halide}$ is $S n {X}_{4}$, i.e. $\text{tin(IV) halide.}$