Question

Question #9db85

Answer 1

`9 * 10^5"g"`

Explanation:

In order to be able to answer this question, you must know the enthalpy of fusion of water

`DeltaH_"fus" = "333.55 J g"^(-1)`

The enthalpy of fusion tells you the amount of energy needed in order to convert `"1 g"` of a given substance from solid at its melting point to liquid at its melting point.

In your case, you know that in order to convert `"1 g"` of ice at `0^@"C"` to liquid water at `0^@"C"`, you need to provide `"333.55 J"`.

You can thus say that `3 * 10^8` `"J"` of heat will melt

`3 * 10^8 color(red)(cancel(color(black)("J"))) * "1 g ice"/(333.55color(red)(cancel(color(black)("J")))) = color(darkgreen)(ul(color(black)(9 * 10^5color(white)(.)"g ice")))`

The answer is rounded to one significant figure.

If you want, you can convert this to kilograms by using the fact that