# Question #87c07

$4$ mol ${H}_{2} S i C {l}_{2} \text{(aq)}$: $4$ mol ${H}_{2} O \text{(l)}$: $1$ mol ${H}_{8} S {i}_{4} {O}_{4} \text{(s)}$: $8$ mol $H C l \text{(aq)}$
The molar ratios of the reagents in chemical reactions are simply the ratios of the coefficients in front of them, which are $4 : 4 : 1 : 8$, respectively.