# Question #a967c

May 25, 2017

$4.4 g$ of $C {O}_{2}$ at STP has a volume of 2.2 L.

#### Explanation:

First, you start off with your given $4.4 g$ of $C {O}_{2}$. You convert it into moles using the Periodic Table. This may vary according to the atomic mass numbers on your Periodic Table.

On my version of the Periodic Table, 1 mol of Carbon has a mass of $12.0111 g$ and 1 mol of Oxygen has a mass of 15.9994 grams.

So 1 mol of $C {O}_{2}$ is $12.0111 \cdot \left(15.9994 \cdot 2\right) = 44.0099 g$.

$\frac{4.4}{44.0099}$ gives you $0.10 m o l$ (2 significant figures).

1 mol of any gas will be equal to 22.4 L at STP. So $0.10$ $m o l$ $C {O}_{2}$ $\cdot$ $22.4 L = 2.2 L$ of $C {O}_{2}$ at STP. (2 significant figures)