# Question 708b0

$104 \text{g H"_2"O}$
We can use the molar mass of water ($\text{H"_2"O}$), which is $18.02 \text{g"/"mol}$, to convert from moles of water to grams of water:
5.75 cancel("mol H"_2"O")((18.02"g H"_2"O")/(1cancel("mol H"_2"O"))) = color(red)(104"g H"_2"O"#