Question

Question #c0ac4

Answer 1

See below.

Explanation:

`"Fe(s) + 2H"^"+""(aq)" ⇌ "H"_2"(g)" + "Fe"^"2+""(aq)"`

If the concentration of `"H"^"+"` were increased, the reaction would respond by trying to get rid of the added `"H"^"+"`.

The position of equilibrium would shift to the right and the concentration of `"H"_2` would increase.

The amount of solid does not affect the position of equilibrium.

If some `"Fe"` were removed, there would be no change in the concentration of `"Fe"^"2+"`.

If the concentration of `"H"_2` were increased, the reaction would respond by trying to get rid of the added `"H"_2`.

The position of equilibrium would shift to the left and the mass of `"Fe"` would increase.