Question #c0ac4

1 Answer
May 25, 2017

Answer:

See below.

Explanation:

#"Fe(s) + 2H"^"+""(aq)" ⇌ "H"_2"(g)" + "Fe"^"2+""(aq)"#

If the concentration of #"H"^"+"# were increased, the reaction would respond by trying to get rid of the added #"H"^"+"#.

The position of equilibrium would shift to the right and the concentration of #"H"_2# would increase.

The amount of solid does not affect the position of equilibrium.

If some #"Fe"# were removed, there would be no change in the concentration of #"Fe"^"2+"#.

If the concentration of #"H"_2# were increased, the reaction would respond by trying to get rid of the added #"H"_2#.

The position of equilibrium would shift to the left and the mass of #"Fe"# would increase.