Question #97fb1
1 Answer
Explanation:
We're asked to find the components of a vector, given its magnitude and direction.
Vectors are a fundamental concept in linear algebra and physics, so it would be useful to remember some relatively simple equations to calculate the components of them.
For magnitude
-
#ul(x = ||vecv||costheta# -
#ul(y = ||vecv||sintheta#
(You may recognize these for calculating the corresponding rectangular coordinate of a polar one, where we use the equations
#x = rcostheta# abd#y = rsintheta# .)
Thus, we have
#x = 50cos(5^"o") = 49.810#
#y = 50sin(5^"o") = 4.358#
Or, in unit vector component notation,
#color(red)(ulbar(|stackrel(" ")(" "49.810hati +4.358hatj" ")|)#
#hati# corresponds to the#x# -component (horizontal), and#hatj# corresponds to the#y# -component (vertical).