Question #c2612
1 Answer
Dec 30, 2017
Explanation:
#cscx=1/sinx=-5rArrsinx=-1/5#
#sinx<0" and "tanx>0#
#rArr"third quadrant where cos is negative"#
#cosx=-sqrt(1-sin^2x)#
#color(white)(cosx)=-sqrt(1-(-1/5)^2)=-sqrt(24/25)=-(2sqrt6)/5#