If there are #115.6*L# of fluorine gas at #"STP"#, what is the molar quantity?

1 Answer
May 25, 2017

Answer:

Approx. #5*mol#.................

Explanation:

The molar volume of an Ideal Gas at #"STP"# is #22.4*L#, and thus number of moles #="volume of gas"/"molar volume"#. We assume that behaviour of #F_2(g)# approaches ideality.

#=(115.6*cancelL)/(22.4*cancelL*mol^-1)=5.16*1/(mol^-1)#

#=5.16*1/(1/(mol))=5.16*mol#.

What is the mass of this quantity of gas?