# Question #3b198

##### 1 Answer

May 28, 2017

#### Explanation:

As an alternative approach, you can start by saying that **largest number** in the sequence.

In this case, the number that comes *before*

Similarly, the number that comes *before* the number that comes before

You know that the sum of the three consecutive integers is equal to

#(x-2) + (x-1) + x = 36#

This is equivalent to

#3x - 3 = 36#

Add

#3x - color(red)(cancel(color(black)(3))) + color(red)(cancel(color(black)(3))) = 36 + 3#

#3x = 39#

Finally, divide both sides by

#(color(red)(cancel(color(black)(3)))x)/color(red)(cancel(color(black)(3))) = 39/3#

to get

#color(darkgreen)(ul(color(black)(x = 13)))#