# What mass is associated with 5.74xx10^22 "titanium atoms"?

Jun 1, 2017

Approx. $5 \cdot g$...........

#### Explanation:

By definition, a $47.9 \cdot g$ mass of titanium contains ${N}_{A}$ $\text{titanium atoms}$, i.e. $6.022 \times {10}^{23}$ individual titanium atoms.

And so we work out the molar quantity of titanium atoms present:

$\left(5.74 \times {10}^{22} \cdot \text{titanium atoms")/(6.022xx10^23*"titanium atoms} \cdot m o {l}^{-} 1\right) = 0.0953 \cdot m o l$.

And then we multiply the molar quantity by the molar mass:

0.0953*molxx47.9*g*mol^-1=??*g.

Capisce?