What mass is associated with #5.74xx10^22# #"titanium atoms"#?

1 Answer
Jun 1, 2017

Answer:

Approx. #5*g#...........

Explanation:

By definition, a #47.9*g# mass of titanium contains #N_A# #"titanium atoms"#, i.e. #6.022xx10^23# individual titanium atoms.

And so we work out the molar quantity of titanium atoms present:

#(5.74xx10^22*"titanium atoms")/(6.022xx10^23*"titanium atoms"*mol^-1)=0.0953*mol#.

And then we multiply the molar quantity by the molar mass:

#0.0953*molxx47.9*g*mol^-1=??*g#.

Capisce?