Question

What mass is associated with `5.74xx10^22` `"titanium atoms"`?

Answer 1

Approx. `5*g`...........

Explanation:

By definition, a `47.9*g` mass of titanium contains `N_A` `"titanium atoms"`, i.e. `6.022xx10^23` individual titanium atoms.

And so we work out the molar quantity of titanium atoms present:

`(5.74xx10^22*"titanium atoms")/(6.022xx10^23*"titanium atoms"*mol^-1)=0.0953*mol`.

And then we multiply the molar quantity by the molar mass:

`0.0953*molxx47.9*g*mol^-1=??*g`.

Capisce?