# Question #19d6f

Jun 1, 2017

5.46x${10}^{22}$ atoms of Chlorine
1.56g Chloral Hydrate will contain 1g Cl
500 moles of Carbon weighs 6 Kg

#### Explanation:

We're going to be using this formula a lot for these questions;
Number of moles = $\frac{M a s s}{M o l a r M a s s}$

Number of molecules in a mole = 6.023x${10}^{23}$

Molar Mass (${C}_{2} {H}_{3} C {l}_{3} {O}_{2}$) = 165.4g
Number of moles of Chloral Hydrate = Mass/Molar Mass
= 0.0302.... moles.
Number of molecules of Chloral Hydrate = 6.023x${10}^{23}$ x 0.0302... = 1.821...x${10}^{22}$
3 atoms of chlorine per molecule of chloral hydrate.
Therefore, number of atoms of chlorine = 1.821...x${10}^{22}$ x 3 = 5.46386453x${10}^{22}$ = 5.46x${10}^{22}$

Number of moles of Chlorine atoms in 1g = 1/35.45 = 0.0282... moles
One molecule of chloral hydrate contains three chlorine atoms, therefore 1/3 of 0.0282... moles of chloral hydrate molecules are needed.
Number of moles of Chloral Hydrate needed = $\frac{0.0282 \ldots}{3}$ = 9.4029...x${10}^{-} 3$
Mass = Number of moles x Molar Mass = 9.4029...x${10}^{-} 3$ x 165.4 = 1.55524...g = 1.56g

Mass of 500 moles of Carbon = 500 x 12 = 6000g = 6 Kg