# What is the mass of a SINGLE ""^32S atom?

Jun 1, 2017

$\text{Mass of ONE atom of sulfur} \equiv 5.31 \times {10}^{-} 23 \cdot g$

#### Explanation:

Well we know that $1 \cdot m o l$ of ""^32S has a mass of $32 \cdot g$.

$32 \cdot g$.

And so we take the quotient..............

$= \frac{32 \cdot g \cdot \cancel{m o {l}^{-} 1}}{6.022 \times {10}^{23} \cdot \cancel{m o {l}^{-} 1}} = 5.31 \times {10}^{-} 23 \cdot g$.