How many moles of oxygen are there in a #1.05 *mmol# quantity of #"aluminum nitrate"#?

1 Answer
anor277
Jun 2, 2017

There are #9.45*mmol# of oxygen atoms.............

Explanation:

Clearly, #1*mol# #Al(NO_3)_3# contains #9*mol# of oxygen atoms, i.e. #9xxN_A# #"oxygen atoms"#, where #N_A="Avogadro's Number"# #-=# #6.022xx10^23*mol^-1#.

And thus in a #1.05*mmol# quantity of #"aluminum nitrate"#, there are #9xx1.05xx10^-3*molxx6.022xx10^23*mol^-1="?? oxygen atoms"#

What is the mass of this molar quantity?

Related questions
See all questions in The Mole
Impact of this question
2376 views around the world
You can reuse this answer
Creative Commons License