How many moles of oxygen are there in a #1.05 *mmol# quantity of #"aluminum nitrate"#?

1 Answer
anor277
Jun 2, 2017

There are #9.45*mmol# of oxygen atoms.............

Explanation:

Clearly, #1*mol# #Al(NO_3)_3# contains #9*mol# of oxygen atoms, i.e. #9xxN_A# #"oxygen atoms"#, where #N_A="Avogadro's Number"# #-=# #6.022xx10^23*mol^-1#.

And thus in a #1.05*mmol# quantity of #"aluminum nitrate"#, there are #9xx1.05xx10^-3*molxx6.022xx10^23*mol^-1="?? oxygen atoms"#

What is the mass of this molar quantity?

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