# Question #5a399

Jun 4, 2017

I get none of the options.

#### Explanation:

Using the expression for heat gained by an object of mass $m$ having specific heat capacity $s$

$Q = m s \Delta T$
where $\Delta T$ is the rise in temperature of object

Inserting given values we get in SI units
$230 = \frac{12.3}{1000} \times s \times \left(67 - 34\right)$
$\implies s = \frac{230 \times 1000}{12.3 \times \left(67 - 34\right)}$
$\implies s = 567 \text{ J"//"kg"^@"C}$