Question #5a399

1 Answer
Jun 4, 2017

Answer:

I get none of the options.

Explanation:

Using the expression for heat gained by an object of mass #m# having specific heat capacity #s#

#Q=msDeltaT#
where #DeltaT# is the rise in temperature of object

Inserting given values we get in SI units
#230=12.3/1000xxsxx(67-34)#
#=>s=(230xx1000)/(12.3xx(67-34))#
#=>s=567" J"//"kg"^@"C"#