#"the mean is just the usual average so sum the values and "#
#"divide by the amount there are"#
#rArr" mean " barx=248/16=15.5#
#"mode is the value that occurs most often"#
#"in this case there are 2 values that occur 3 times each"#
#rArr"mode "=13" and " 14#
#"range "=" largest - smallest"#
#"to obtain median require to arrange data in ascending order"#
#11,12,12,13,color(magenta)(uarr)13,13,14,14,color(red)(uarr)14,15,17,18,color(magenta)(uarr)18#
#19,22,23#
#"the median "color(red)(Q_2)" is the middle value"#
#rArrcolor(red)(Q_2)=(14+14)/2=14larr" average of value either side"#
#"lower/upper quartiles " color(magenta)(Q_1)" and " color(magenta)(Q_3)" divides the values"#
#"on either side of the median into 2 equal parts"#
#color(magenta)(Q_1)=(13+13)/2=13#
#color(magenta)(Q_3)=(18+18)/2=18#
#"Min " =11" and Max "=23#
#"you now have the 5 number summary required to "#
#"draw the box-plot"#
#"inter-Quartile range " (IQR)=color(magenta)(Q_3)-color(magenta)(Q_1)#
#color(white)(xxxxxxxxxxxxxxxxxxx)=18-13=5#