Question #25e36

1 Answer
Jun 5, 2017

#"see explanation"#

Explanation:

#"the mean is just the usual average so sum the values and "#
#"divide by the amount there are"#

#rArr" mean " barx=248/16=15.5#

#"mode is the value that occurs most often"#

#"in this case there are 2 values that occur 3 times each"#

#rArr"mode "=13" and " 14#

#"range "=" largest - smallest"#

#rArr"range "=23-11=12#

#"to obtain median require to arrange data in ascending order"#

#11,12,12,13,color(magenta)(uarr)13,13,14,14,color(red)(uarr)14,15,17,18,color(magenta)(uarr)18#

#19,22,23#

#"the median "color(red)(Q_2)" is the middle value"#

#rArrcolor(red)(Q_2)=(14+14)/2=14larr" average of value either side"#

#"lower/upper quartiles " color(magenta)(Q_1)" and " color(magenta)(Q_3)" divides the values"#
#"on either side of the median into 2 equal parts"#

#color(magenta)(Q_1)=(13+13)/2=13#

#color(magenta)(Q_3)=(18+18)/2=18#

#"Min " =11" and Max "=23#

#"you now have the 5 number summary required to "#
#"draw the box-plot"#

#"inter-Quartile range " (IQR)=color(magenta)(Q_3)-color(magenta)(Q_1)#

#color(white)(xxxxxxxxxxxxxxxxxxx)=18-13=5#