# How many "neutrons", massive, neutrally charged nuclear particles, are present in a 2*mol quantity of water?

Jun 5, 2017

Well, there are $2 \cdot m o l$ of water.........and approx. $96 \times {10}^{23}$ individual neutrons.
And in each water molecule, i.e. ${\text{^1H_2}}^{16} O$, where we treat the water molecule as AN ISOTOPOMER than contains $\text{8 neutrons}$, clearly there are $8 \cdot m o l$ of neutrons.
And a mole, $\text{Avogadro's Number}$, specifies ${N}_{A}$, $6.022 \times {10}^{23}$ individual items of stuff. So we have approx. $16 \times {N}_{A} \cong 96 \times {10}^{23}$ individual neutrons.
I really can use mental arithmetic here; the numbers are so impossibly large that $\text{near enuff is good enuff}$.