How many #"neutrons"#, massive, neutrally charged nuclear particles, are present in a #2*mol# quantity of water?

1 Answer
anor277
Jun 5, 2017

Well, there are #2*mol# of water.........and approx. #96xx10^23# individual neutrons.

Explanation:

And in each water molecule, i.e. #""^1H_2""^16O#, where we treat the water molecule as AN ISOTOPOMER than contains #"8 neutrons"#, clearly there are #8*mol# of neutrons.

And a mole, #"Avogadro's Number"#, specifies #N_A#, #6.022xx10^23# individual items of stuff. So we have approx. #16xxN_A~=96xx10^23# individual neutrons.

I really can use mental arithmetic here; the numbers are so impossibly large that #"near enuff is good enuff"#.

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