# Question 80740

Jun 5, 2017

$\text{Molarity} = 0.500 \cdot m o l \cdot {L}^{-} 1$

#### Explanation:

By definition, $\text{molarity"="moles of solute"/"volume of solution}$.

And for this problem, we get:

((5.3*g)/(105.99*g*mol^-1))/(100*mLxx10^-3*L*mL^-1)=??*mol*L^-1#

What is the concentration with respect to $N {a}^{+}$ ion?