# How many particles are present in an 8*g mass of dioxygen molecules under different conditions of pressure and temperature?

Jun 7, 2017

An $8 \cdot g$ mass of dioxygen gas contains the same number of molecules under any conditions.............

#### Explanation:

And number of molecules.....

$= \text{Mass"/"Molar mass of dioxygen} \times {N}_{A}$, where ${N}_{A}$ $=$ $\text{Avogadro's number,}$ $6.022 \times {10}^{23} \cdot m o {l}^{-} 1$,

$= \frac{8 \cdot g}{32.00 \cdot g \cdot m o {l}^{-} 1} \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$

$= \frac{1}{4} \times {N}_{A} \cong 1.5 \times {10}^{23}$..............