# How many electrons in a 196*g mass of sulfuric acid?

Approx. $3 \times {10}^{25}$ $\text{electrons}$.
In one MOLECULE of ${H}_{2} S {O}_{4}$, there are $2 \times 1 \left(H\right) + 16 \left(S\right) + 4 \times 8 \left(O\right) = 50$ electrons in total.
But we have a molar quantity of $\frac{196 \cdot g}{98.08 \cdot g \cdot m o {l}^{-} 1} = 2 \cdot m o l$. And given that there are $\text{Avogadro's number,}$ $6.022 \times {10}^{23} \cdot {\text{particles mol}}^{-} 1$, we have ${N}_{A} \times 50 \cdot \text{electrons}$
$= 3 \times {10}^{25}$ $\text{electrons}$............anyway, do this on your calculator and see if I have got the arithmetic right for once.