# Question 2a6d3

Jun 11, 2017

${\text{4.7 dm}}^{3}$

#### Explanation:

Well, all you really have to do here is to use the known concentration of the solution as a conversion factor to go from mass of potassium permanganate to volume of solution.

You know that this solution has a concentration of ${\text{3.17 g dm}}^{- 3}$, which basically means that you get $\text{3.17 g}$ of potassium permanganate, the solute, for every ${\text{1 dm}}^{3}$ of solution.

"3.17 g dm"^(-3) = "3.17 g KMnO"_4/("1 dm"^3color(white)(.)"solution")

In your case, you want to go from grams of potassium permanganate to cubic decimeters of solution, so rewrite the conversion factor as

("1 dm"^3color(white)(.)"solution")/"3.17 g KMnO"_4#

Use this to calculate the volume of solution that contains $\text{15 g}$ of solute

$15 \textcolor{red}{\cancel{\textcolor{b l a c k}{\text{g KMnO"_4))) * ("1 dm"^3color(white)(.)"solution")/(3.17color(red)(cancel(color(black)("g KMnO"_4)))) = color(darkgreen)(ul(color(black)("4.7 dm"^3color(white)(.)"solution}}}}$

The answer is rounded to two sig figs, the number of sig figs you have for the mass of potassium permanganate.