Question

Question #f3694

Answer 1

The value of the car is never equal to zero for `x in RR`.

Explanation:

The function for the value of the car is given as `v = 40,000 (1- 0.3)^(x) = 40,000 (0.7)^(x)`

We need to find when the value is zero, so let's set `v` equal to zero:

`Rightarrow v = 0`

`Rightarrow 40,000 (0.7)^(x) = 0`

Dividing both sides by `40,000`:

`Rightarrow (0.7)^(x) = 0`

At this point, we cannot go any further algebraically to try and solve for `x`.

There are no real solutions to the equation.

Therefore, the value of the car is never equal to zero for `x in RR`.