Question

Question #5cc63

Answer 1

Ahhh, we can used permuatations:

Explanation:

Let's use factorials, firstly:

`!` (These things)

So, to find all the possible combinations, we know that there are, in total, `12` variables, `b1 , b2, b3` etc.

So, the amount of total possible arrangements are:

`12!`

= `479001600`

That's a pretty big number...

Now, out of these combinations, we know that there are:

`6!` ways that the girls can sit together...

= `720`

Therefore, we can now find the amount of ways that the girls can sit together, and the amount of ways the girls sit together, respectively:

Ways (Boys/Girls) = `479001600 - 720` = `479000880`

Ways (Girls) = `720`

Therefore, the probability that the girls sit together is:

`479001600/720`

And the probability that the boys and girls sit together in a seperate combination is:

`479000880/479001600`

What? You said `g1 = g6`?!

That's for another time, my young friend...