Question #09a4c

1 Answer
Jun 13, 2017

-1/3sqrt((1-2x)^3)+C

Explanation:

int sqrt(1-2x) dx
Let u=1-2x
then du=-2dx
i.e. dx=(du)/-2
int sqrt(1-2x) dx
=intsqrtu(du)/-2
=-1/2intu^(1/2)du
=-1/2(u^(3/2)/(3/2))
=-1/3sqrt(u^3)
Substituting u=1-2x back into the integral,
=-1/3sqrt((1-2x)^3)+C