A train is moving at a constant velocity of #"5 m/s"#. After it exists a tunnel, it starts to accelerate with an acceleration of #"9 m/s"^2# for #"5 s"#. What is the velocity of the train after #"5 s"# ?

1 Answer
Jun 14, 2017

Answer:

#50# #"m/s"#

Explanation:

We're asked to find the velocity of the train after #5# #"s"# with a given initial velocity and acceleration.

To solve this, we can use the equation

#v_x = v_(0x) + a_xt#

where

  • #v_x# is the velocity at time #t# (what we're trying to find)

  • #v_(0x)# is the initial velocity (#5# #"m/s"#)

  • #a_x# is the acceleration (#9# #"m/s"^2#)

  • #t# is the time (#5# #"s"#)

Plugging in known values, we have

#v_x = 5"m/s" + (9"m/s"^2)(5"s") = color(red)(50# #color(red)("m/s"#

The final velocity (the velocity at time #t = 5# #"s"#) is thus #color(red)(50# meters per second.