A train is moving at a constant velocity of #"5 m/s"#. After it exists a tunnel, it starts to accelerate with an acceleration of #"9 m/s"^2# for #"5 s"#. What is the velocity of the train after #"5 s"# ?
1 Answer
Jun 14, 2017
Answer:
Explanation:
We're asked to find the velocity of the train after
To solve this, we can use the equation
where

#v_x# is the velocity at time#t# (what we're trying to find) 
#v_(0x)# is the initial velocity (#5# #"m/s"# ) 
#a_x# is the acceleration (#9# #"m/s"^2# ) 
#t# is the time (#5# #"s"# )
Plugging in known values, we have
The final velocity (the velocity at time