# Question #34b29

1 mol of ${\text{C"_3"H}}_{8}$ contains 3 mol of $\text{C}$ atoms and 8 mol of $\text{H}$ atoms for a total of 11 mol of atoms.
So, it has 11 mol of atoms for every 3 mol of $\text{C}$ atoms.
$\text{Moles of atoms" = 11.6 color(red)(cancel(color(black)("mol C atoms"))) × "11 mol atoms"/(3 color(red)(cancel(color(black)("mol C atoms")))) = "42.5 mol atoms}$