# Question #2a761

Jun 16, 2017

You can find this by adding the atomic mass units (AMU) of the atoms (elements) that make up $C {O}_{2}$:
$m \left(C\right) = 12 , m \left(O\right) = 16$
So $m \left(C {O}_{2}\right) = 12 + 2 \times 16 = 44 g / m o l$
$N \left(C {O}_{2}\right) = \frac{2000 g}{44 g / m o l} \approx 45.5 m o l$