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Answer 1 · 2017-06-17T08:08:35

#f(x+2)=x^2+4x+7#

we have

#f(x)=x^2+3#

#f(x+2)" "#means that we replace all the #xs# in the function with #(x+2)#

so

#f(x+2)=color(red)((x+2)^2)+3#

we now multiply out and simplify

#f(x+2)=color(red)(x^2+4x+4)+3#

#f(x+2)=x^2+4x+7#

I think you may have multiplied the brackets out incorrectly.