# How many electrons are associated with a 4.2*g mass of nitride anion?

Jun 17, 2017

Well in one mole of nitride anion.........there are $1.44 \times {10}^{24}$ $\text{electrons.}$

#### Explanation:

Well in one formula unit of $\text{nitride anion.........}$, there are $3 \times 7 + 3 = 24 \cdot \text{electrons}$.

And in $\text{one mole}$ of anything there are $6.022 \times {10}^{23}$ individual items, or there are $6.022 \times {10}^{23} \cdot \text{particles} \cdot m o {l}^{-} 1$.

$\text{Moles of nitride anion} = \frac{4.2 \cdot g}{42.03 \cdot g \cdot m o {l}^{-} 1} = 1.0 \times {10}^{-} 1 \cdot m o l$.

And thus $\text{number of electrons..................}$

$= 1 \times {10}^{-} 1 \cdot m o l \times 24 \cdot \text{electrons} \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$

$= 1.45 \times {10}^{24} \cdot \text{electrons.............}$