# Question #71d2a

##### 2 Answers

Jun 17, 2017

See a solution process below:

#### Explanation:

First, rewrite the third term as:

We can now factor and

We can now factor the quadratic as:

Or

Jun 17, 2017

#x^2(a-b)-6x(a-b)-(-9)(a-b)# , taking -1 common from the last bracket.

=#x^2(a-b)-6x(a-b)+9(a+b)#

Taking (a-b) common from the whole expression we get

#(a-b)(x^2 -6x+9)#

So, the expression can be factorised as

#x^2(a-b)-6x(a-b)-9(b-a)=(a-b)(x-3)^2#

Hope this helps.

Feel free to comment if you want further explanation of any step.