# If we require 445*g of copper metal, what mass of CuFeS_2 ore do we need?

Jun 17, 2017

#### Answer:

Good question! We need approx. $1.3 \cdot k g$ of ore.....

#### Explanation:

We want $\frac{445 \cdot g}{63.55 \cdot g \cdot m o {l}^{-} 1} = 7.00 \cdot m o l$ $\text{copper metal}$.

Given that we have $C u F e {S}_{2}$, we need AT LEAST $7.00 \cdot m o l$ of this ore.........

i.e. a mass of 183.54*g*mol^-1xx7.00*mol=??*g.