Question #e4dde

1 Answer
Jun 19, 2017

Answer:

#1.56 xx 10^21# #"atoms Na"#

#= 0.00259# #"mol Na"#

#= 0.0596# #"g Na"#

Explanation:

Your answer is in the question: #1.56 xx 10^21# atoms of #"Na"# is equal to #1.56 xx 10^21# atoms of #"Na"#.

If you would like to find the number of moles present, you can use Avogadro's number to find this:

#1.56 xx 10^21 cancel("atoms Na")((1color(white)(l)"mol Na")/(6.022 xx 10^23cancel("atoms Na")))#
#= color(red)(0.00259# #color(red)("mol Na"#

You can also find the mass of sodium present, using the molar mass of sodium, #22.99"g"/"mol"# (found on a periodic table):

#color(red)(0.00259# #cancel(color(red)("mol Na"))((22.99color(white)(l)"g Na")/(1cancel("mol Na"))) = color(blue)(0.0596# #color(blue)("g Na"#