# Question #e50ee

$9.7 \times {10}^{- 3}$ mol C contains $5.8 \times {10}^{21}$ atoms C.
You need to multiply the moles C by $6.022 \times {10}^{23} \text{atoms /mol C}$.
$\text{1 mol C atoms"=6.022xx10^23 "atoms C}$
$9.7 \times {10}^{- 3} \text{mol C"xx(6.022xx10^23"atoms C")/(1"mol C")=5.8xx10^21 "atoms C}$