Question #e50ee

1 Answer
Meave60
Jun 20, 2017

#9.7xx10^(-3)# mol C contains #5.8xx10^21# atoms C.

Explanation:

You need to multiply the moles C by #6.022xx10^23"atoms /mol C"#.

#"1 mol C atoms"=6.022xx10^23 "atoms C"#

#9.7xx10^(-3)"mol C"xx(6.022xx10^23"atoms C")/(1"mol C")=5.8xx10^21 "atoms C"#

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