How do we formulate the reaction between aluminum and chlorine gas? What is the molar equivalence?

1 Answer
Sep 6, 2017

Answer:

We wants to make #AlCl_3#.........

Explanation:

Aluminum metal comes from Group 13 of the Periodic Table; it typically forms the #Al^(3+)# cation on oxidation......Meanwhile chlorine comes from Group 17. It is typically reduced to give the chloride ion, #Cl^-#.

And so #Al^(3+) + 3xxCl^-# and we gets #AlCl_3# as the neutral salt; in the solid phase it is probably the chloro-bridged dimer, #{Cl_2Al}_2(mu"-"Cl)_2#....