Question #7baa6

1 Answer
Jun 21, 2017

Answer:

Well, we know that #1*mol# of Ideal gas at #"STP"# occupies #22.4*L#...

Explanation:

And thus if we assume that carbon dioxide behaves ideally (which is a reasonable assumption, then we have #(224*L)/(22.4*L*mol^-1)#, i.e. a #10*mol# quantity of #CO_2#.....And I think you can see why they specified this particular volume.

And thus there is a #10*mol# quantity of carbon, i.e. #10*molxx12.00*g*mol^-1=120.0*g#........

And likewise there is #20*molxx15.999*g*mol^-1=320.0*g#........with respect to #"oxygen"#.

And you should not have to remember the atomic masses (tho you will soon retain the common masses) because you should be provided with a Periodic Table.