# How many carbon atoms in a 6*g mass of glucose?

Jun 21, 2017

Approx. ${10}^{23}$ individual carbon atoms........

#### Explanation:

We know that glucose, ${C}_{6} {H}_{12} {O}_{6}$, has a molar mass of $180.16 \cdot g \cdot m o {l}^{-} 1$.

And so (i) we calculate the molar quantity of the $6 \cdot g$ mass......

$\text{Moles of glucose} \equiv \frac{6 \cdot g}{180.16 \cdot g \cdot m o {l}^{-} 1} = 0.0333 \cdot m o l$

And so we gots $0.0333 \cdot m o l$ of glucose; but we further know that IN EACH MOLE of glucose there are six moles of carbon...

And so there are (ii).....................

$0.0333 \cdot m o l \times 6 \cdot \text{atoms} \times {N}_{A} = 0.200 \cdot m o l \times {N}_{A}$

i.e. $0.200 \cdot m o l \times 6.022 \times {10}^{23} \cdot m o {l}^{-} 1 = 1.20 \times {10}^{23} \cdot \text{carbon atoms.}$