Question #1a288

1 Answer
Jun 27, 2017

There are #1.00 × 10^26# atoms in 1 L of water.

Explanation:

Step 1. Calculate the mass of the water

#"Mass" = 1000 color(red)(cancel(color(black)("mL water"))) × "1 g water"/(1 color(red)(cancel(color(black)("mL water")))) = "1000 g water"#

Step 2. Calculate the moles of water

#"Moles of water" = 1000 color(red)(cancel(color(black)("g water"))) × "1 mol water"/(18.02 color(red)(cancel(color(black)("g water")))) = "55.49 mol water"#

Step 3. Calculate the molecules of water

#"Molecules of H"_2"O" = 55.49 color(red)(cancel(color(black)("mol H"_2"O"))) × (6.022 × 10^23 color(white)(l)"molecules H"_2"O")/(1 color(red)(cancel(color(black)("mol H"_2"O"))))#

#= 3.342 × 10^25 color(white)(l)"molecules H"_2"O"#

Step 4. Calculate the number of atoms

Each molecule of #"H"_2"O"# contains three atoms.

#"No. of atoms" = 3.342 × 10^25 color(red)(cancel(color(black)("molecules H"_2"O"))) × "3 atoms"/(1 color(red)(cancel(color(black)("molecule H"_2"O"))))#

#= 1.00 × 10^26 color(white)(l)"atoms"#