# What are the numbers, and types of atoms in a 245*g mass of sulfuric acid?

Jun 28, 2017

Well, what is the molar quantity of sulfuric acid....?

#### Explanation:

$\text{Moles of sulfuric acid} = \frac{245 \cdot g}{98.08 \cdot g \cdot m o {l}^{-} 1} = 2.50 \cdot m o l$

Given that a molar quantity contains ${N}_{A}$ individual particles of stuff, where ${N}_{A} = 6.022 \times {10}^{23} \cdot m o {l}^{-} 1$.....

There are......

$2.5 \times 2 \times {N}_{A}$ $\text{hydrogen atoms...........}$ $5 {N}_{A}$

$2.5 \times {N}_{A}$ $\text{sulfur atoms...........}$ $2.5 {N}_{A}$

$2.5 \times 4 \times {N}_{A}$ $\text{sulfur atoms...........}$ $10 {N}_{A}$

Jun 28, 2017

There are 3.01 × 10^24 atoms of $\text{H}$, 1.50 × 10^24 atoms of $\text{S}$, and  9.03 × 10^24 atoms of $\text{O}$.

#### Explanation:

Step 1. Calculate the moles of ${\text{H"_2"SO}}_{4}$

${\text{Moles of H"_2"SO"_4 = 245 color(red)(cancel(color(black)("g H"_2"SO"_4))) × ("1 mol H"_2"SO"_4)/(98.08 color(red)(cancel(color(black)("g H"_2"SO"_4)))) = "2.498 mol H"_2"SO}}_{4}$

Step 2. Calculate the molecules of ${\text{H"_2"SO}}_{4}$

${\text{Molecules of H"_2"SO"_4 = 2.498 color(red)(cancel(color(black)("mol H"_2"SO"_4))) × (6.022 ×10^23color(white)(l) "molecules H"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol H"_2"SO"_4)))) = 1.504 ×10^24color(white)(l) "molecules H"_2"SO}}_{4}$

Step 3. Calculate the atoms of each element

"Atoms of H" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "2 atoms H"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4))))

= 3.01 × 10^24 color(white)(l)"atoms H"

"Atoms of S" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "1 atom S"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4)))) =

1.50 × 10^24 color(white)(l)"atoms S"

"Atoms of O" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "4 atoms O"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4))))

= 9.03 × 10^24 color(white)(l)"atoms H"