Question

What are the numbers, and types of atoms in a `245*g` mass of sulfuric acid?

Answer 1

Well, what is the molar quantity of sulfuric acid....?

Explanation:

`"Moles of sulfuric acid"=(245*g)/(98.08*g*mol^-1)=2.50*mol`

Given that a molar quantity contains `N_A` individual particles of stuff, where `N_A=6.022xx10^23*mol^-1`.....

There are......

`2.5xx2xxN_A` `"hydrogen atoms..........."` `5N_A`

`2.5xxN_A` `"sulfur atoms..........."` `2.5N_A`

`2.5xx4xxN_A` `"sulfur atoms..........."` `10N_A`

Answer 2

There are `3.01 × 10^24` atoms of `"H"`, `1.50 × 10^24` atoms of `"S"`, and `9.03 × 10^24` atoms of `"O"`.

Explanation:

Step 1. Calculate the moles of `"H"_2"SO"_4`

`"Moles of H"_2"SO"_4 = 245 color(red)(cancel(color(black)("g H"_2"SO"_4))) × ("1 mol H"_2"SO"_4)/(98.08 color(red)(cancel(color(black)("g H"_2"SO"_4)))) = "2.498 mol H"_2"SO"_4`

Step 2. Calculate the molecules of `"H"_2"SO"_4`

`"Molecules of H"_2"SO"_4 = 2.498 color(red)(cancel(color(black)("mol H"_2"SO"_4))) × (6.022 ×10^23color(white)(l) "molecules H"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol H"_2"SO"_4)))) = 1.504 ×10^24color(white)(l) "molecules H"_2"SO"_4`

Step 3. Calculate the atoms of each element

`"Atoms of H" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "2 atoms H"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4))))`

`= 3.01 × 10^24 color(white)(l)"atoms H"`

`"Atoms of S" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "1 atom S"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4)))) =`

`1.50 × 10^24 color(white)(l)"atoms S"`

`"Atoms of O" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "4 atoms O"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4))))`

`= 9.03 × 10^24 color(white)(l)"atoms H"`