What are the numbers, and types of atoms in a #245*g# mass of sulfuric acid?

2 Answers
Jun 28, 2017

Answer:

Well, what is the molar quantity of sulfuric acid....?

Explanation:

#"Moles of sulfuric acid"=(245*g)/(98.08*g*mol^-1)=2.50*mol#

Given that a molar quantity contains #N_A# individual particles of stuff, where #N_A=6.022xx10^23*mol^-1#.....

There are......

#2.5xx2xxN_A# #"hydrogen atoms..........."# #5N_A#

#2.5xxN_A# #"sulfur atoms..........."# #2.5N_A#

#2.5xx4xxN_A# #"sulfur atoms..........."# #10N_A#

Jun 28, 2017

Answer:

There are #3.01 × 10^24# atoms of #"H"#, #1.50 × 10^24# atoms of #"S"#, and # 9.03 × 10^24# atoms of #"O"#.

Explanation:

Step 1. Calculate the moles of #"H"_2"SO"_4#

#"Moles of H"_2"SO"_4 = 245 color(red)(cancel(color(black)("g H"_2"SO"_4))) × ("1 mol H"_2"SO"_4)/(98.08 color(red)(cancel(color(black)("g H"_2"SO"_4)))) = "2.498 mol H"_2"SO"_4#

Step 2. Calculate the molecules of #"H"_2"SO"_4#

#"Molecules of H"_2"SO"_4 = 2.498 color(red)(cancel(color(black)("mol H"_2"SO"_4))) × (6.022 ×10^23color(white)(l) "molecules H"_2"SO"_4)/(1 color(red)(cancel(color(black)("mol H"_2"SO"_4)))) = 1.504 ×10^24color(white)(l) "molecules H"_2"SO"_4#

Step 3. Calculate the atoms of each element

#"Atoms of H" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "2 atoms H"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4))))#

#= 3.01 × 10^24 color(white)(l)"atoms H"#

#"Atoms of S" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "1 atom S"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4)))) =#

#1.50 × 10^24 color(white)(l)"atoms S"#

#"Atoms of O" = 1.504 ×10^24 color(red)(cancel(color(black)("molecules H"_2"SO"_4))) × "4 atoms O"/(1 color(red)(cancel(color(black)("molecule H"_2"SO"_4))))#

#= 9.03 × 10^24 color(white)(l)"atoms H"#